Question

Satvik is 3 years older than Atharva. six years ago, satvik's age was four times Atharva's age. find the ages of Satvik and Atharva​

Answer 1

AnswEr :

• P R E S E N T ⠀A G E :

⇒ Sathvik is 3 Years Older than Atharva

⇒ S = A + 3⠀⠀⠀⠀—eq. ( I )

• S I X ⠀Y E A R S ⠀A G O :

↠ Sathvik = Four times of Atharva

↠ (S - 6) = 4 × (A - 6)

• Putting the Value of S from eq.( I )

↠ (A + 3 - 6) = 4 × (A - 6)

↠ A - 3 = 4A - 24

↠ 24 - 3 = 4A - A

↠ 21 = 3A

• Dividing both term by 3

↠ A = 7

_______________________________

• P R E S E N T ⠀A G E S :

◗ Sathvik = A + 3 = (7 + 3) = 10 Years

◗ Atharva = A = 7 Years

∴ Present Age of Sathvik and Atharva will be 10 yrs and 7 yrs respectively.

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• V E R I F I C A T I O N :

⇝ Sathvik = Four times of Atharva

⇝ (S - 6) = 4 × (A - 6)

⇝ (10 - 6) = 4 × (7 - 6)

⇝ 4 = 4 × 1

⇝ 4 Years = 4 Years ⠀⠀Hence, Verified!

#answerwithquality #BAL

Answer 2

Answer:

7years , 28 years

Step-by-step explanation:

$let \: the \: age \: of \: atharva \: be \: x \\ age \: of \: satvik = x + 3 \\ x + 3 - 6 + x - 6 = 4x + 6 + x + 6 \\ 2x - 9 = 5x + 12 \\ - 9 - 12 = 5x - 2x \\ - 21 = 3x \\ x = 7 \\ therefore \: age \: of \: atharva = 7years \\ age \: of \: satvik = 4(7) = 28 \: years.$