Question

Satwinder bought two fans for 3605 rupees . She sold at a profit of 15% and other at a loss of 9% . If Satwinder obtained the same amount for each fan ,find the cost of each fan.

Answer 1

Answer:

Cost price of first fan = 1592.5 rupees,

Second fan =2012.5 rupees.

Step-by-step explanation:

Let x be the cost of first fan = x rupees,

∵ Total cost price = 3605 rupees

So, the cost of second fan = (3605 - x) rupees,

Now, profit in first fan = 15%,

Thus, the selling price of first fan = x + 15% of x = x + 0.15x = 1.15x

Also, the loss in second fan = 9%

Thus, the selling price of second fan = 3605 - x - 9% of (3605 - x)

= 3605 - x - 0.09(3605 - x)

= 3605 - x - 324.45 + 0.09x

= 3280.55 -0.91x

According to the question,

1.15x = 3280.55 -0.91x

1.15x + 0.91x = 3280.55

2.06x = 3280.55

$\implies x = \frac{3280.55}{2.06}=1592.5$

Thus, the cost price of first fan = 1592.5 rupees,

Second fan = 3605 - 1592.5 = 2012.5 rupees.

Answer 2

Answer:

Cost price of first fan = 1592.5 rupees,

Second fan =2012.5 rupees.

Step-by-step explanation:

Let x be the cost of first fan = x rupees,

∵ Total cost price = 3605 rupees

So, the cost of second fan = (3605 - x) rupees,

Now, profit in first fan = 15%,

Thus, the selling price of first fan = x + 15% of x = x + 0.15x = 1.15x

Also, the loss in second fan = 9%

Thus, the selling price of second fan = 3605 - x - 9% of (3605 - x)

= 3605 - x - 0.09(3605 - x)

= 3605 - x - 324.45 + 0.09x

= 3280.55 -0.91x

According to the question,

1.15x = 3280.55 -0.91x

1.15x + 0.91x = 3280.55

2.06x = 3280.55

\implies x = \frac{3280.55}{2.06}=1592.5⟹x=

2.06

3280.55

=1592.5

Thus, the cost price of first fan = 1592.5 rupees,

Second fan = 3605 - 1592.5 = 2012.5 rupees.