Satwinder bought two fans for RS 3605.she sold one at a profit of 15% and the other at a loss of 9%.If satwinder obtained the same amount for each fan,find the cost price of each fan.
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Assume that the cost price of the first fan is Rs x
Cost price for the Fan 2 is Rs y.
The total cost price for the fans = x+y = Rs 3605.
Therefore, y = 3605-x …………………………………………….. (1)
He sold Fan 1 at a 15% profit
i.e., x + 15/100 x = 1.15 x
He sold the Fan 2 at a 9% loss;
i.e., y – 9/100 y = 0.91 y …………………………………………(2)
As shown in Eq. 1; y = 3605-x
Substituting in Eq. 2;
= 0.91 y
= 0.91 (3605-x)
As mentioned in the question;
1.15 x = 0.91 (3605 – x)
1.15 x = 3280.55 – 0.91 x
1.15 x + 0.91 x = 3280.55
Thus; 2.06 x = 3280.55
X = 1592.5
Y = 3605- x
= 2012.5
The cost of Fan 1 was Rs. 1592.5
The cost of Fan 2 was Rs. 2012.5
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