Question

Satya observed the top of a tree
at an angle of elevation of 6o
when the observation point was
5m away from the hot of the
tree Draw a diagram for this data)​

Answer 1

Given:

Angle of elevation, θ = 60°

The distance between the observation point and the foot of the tree = 5 m

To find:

Draw a diagram for this data

Solution:

The diagram that satisfies the given data is being attached below.

From the figure attached below we have,

AB = height of the tree

C = point of observation

BC = the distance between the observation point and the foot of the tree

∠ACB = 60° = angle of elevation

The formula to be used:

Trigonometric ratios of the triangle: tan θ =   $\frac{perpendicular}{base}$

Considering Δ ABC, we have

AB = perpendicular

BC = base

θ = 60°

∴ tan 60° =   $\frac{AB}{BC}$

⇒ √3 =   $\frac{AB}{5}$

⇒ AB = 5√3 m  

Thus, the height of the tree is 5√3 m.

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Also View:  

From the top of building 20m high the angle of elevation of the top of tower is 30degree and the angle of depression of foot of the same pole is 60 degree find the height of the pole?  

https://brainly.in/question/15769123  

The angle of elevation of a cloud the angle of elevation of a cloud from a point 60m above a lake is 30 degree and the angle of depression of reflection of the cloud in the lake is 60 degree find the height of the cloud from the surface of the lake ​

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Answer 2

Diagram of the given observation:

1) We all know very well that the tree is perpendicular to the ground so this will be the case of the right angle triangle.

2) The angle of the elevation means that the Satya was observing a point which is above from its level of sight.

3) The diagram is given in the attached picture.