saumya does 1/2 of the work in 7 days and rupam does 1/7 of the work in 4 days and abik does 60% of the work in 15 days in .how many days saumya and abik together do the work?
Answers
Answered by
2
9 days
Step-by-step explanation:
S alone => 2×7/1 = 14 days
R alone = 7×4 = 28 days & A alone
= 5× 15/3 = 25 days
(Note : 60% = 60/100 =3/5)
Total Work = LCM (14,28,25) = 700 units
Efficiencies of ;
S = 700/14=50 units/d &A=700/25=28 u/d
together (S + A) can do it in ;
= 700/(50+28) = 700/78 = 8.97
~ = 9 days .
Similar questions