Saurabh borrowed Rs 36000 to buy a computer at 10% per annum. Find the amount that Saurabh
would need to pay after
2¼ Years
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Answer:
Rs.8100
Step-by-step explanation:
A = final amount
P = initial principal balance
r = annual interest rate
t = time (in years)
A = P (1 + rt)
P = Rs.36000
r = 10%
t = 2Years, 3Months
A = 36000(1+10/100×2.25)
2.25 Can Be Written As 225/100
36000(1+225/1000)
36000(1+9/40)
36000(40/40+9/40)
36000(49/40)
324000/40 = Rs.8100
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