Saurabh has Rs. 34 fifty paise and twenty five paise coins. If the number of 25 paise
coins be twice the number of 50 paise coins , how many coins of each coins does he
have?
Answers
Answered by
5
let me convert 34 into paisas=34 x 100=3400ps.
50 ps = a ,25ps = 2a
a x 50 + 2a x25 =3400
100a =3400
a=3400/100
a=34
50ps=34 coins
25ps=68 coins
Answered by
3
Let Sumitra has 'x' 50-paise coins & 'y' 25-paise coins.
She has rs 34
So rs 1 = 100 paise
rs 34 = 34*100 = 3400 paise
50x + 25y = 3400 ----------- (1)
Given that , y = 2x ------------(2)
from equation (1) & (2) we get
50x + 25*(2x) = 3400
50x + 50x = 3400
100x = 3400
x = 34
From (2) we get
y = 2x = 2*34 = 68
So,
Number of 50-paise coins = 34
Number of 25-paise coins = 68
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