Saurabh
has rupees 34 50 paise and 25 paise coins if the number of 25 paise coin to twice the number of 50 paise coins how many coins of each kind does he have
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let the 25 paise coin be 2x
50 paise cpin be x
amount of 25 paise coin= 25× 2x=50x
amount of 50 paise coin=50× x= 50x
A.t.q
50x+50x=3400 paise
100x= 3400/100x
x= 34
so, no of 25 paise coin= 2×34=68
no of 50 paise coin= 34
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