Question

Saurav lends Rs 12000 to Vikas for 4 years and Rs 30,000 to Naresh for 6 years at the same rate of interest total interest received from both is Rs 2400 find the rate of interest​

Answer 1

The rate is 1.05%

Step-by-step explanation:

• Since, Saurabh lends Rs 12000 for 4 years at the rate of r% (say).

• So, $SI_1 = \dfrac{P\times r\times t}{100}$

• $SI_1 = \dfrac{12000\times r\times 4}{100}$

• $SI_1 = 480r$  ............(1)

Similarly, Saurabh lends Rs 30000 for 6 years at the rate of r%.

Therefore, $SI_2 = \dfrac{P\times r\times t}{100}$

• $SI_2 = \dfrac{30000\times r\times 6}{100}$

• $SI_2 = 1800r$  ........(2)

The sum of both interests is Rs 2400.

• $SI_1 + SI_2 = 2400$

           480r + 1800r = 2400

                       2280r = 2400

$r = \dfrac{240}{228}\%$

• r = 1.05%

Thus, the rate is 1.05%.

Answer 2

The rate is 1.05%

Step-by-step explanation:

Since, Saurabh lends Rs 12000 for 4 years at the rate of r% (say).

So, SI_1 = \dfrac{P\times r\times t}{100}SI1=100P×r×t

SI_1 = \dfrac{12000\times r\times 4}{100}SI1=10012000×r×4

SI_1 = 480rSI1=480r  ............(1)

Similarly, Saurabh lends Rs 30000 for 6 years at the rate of r%.

Therefore, SI_2 = \dfrac{P\times r\times t}{100}SI2=100P×r×t

Therefore, SI_2 = \dfrac{P\times r\times t}{100}SI2=100P×r×t

SI_2 = \dfrac{30000\times r\times 6}{100}SI2=10030000×r×6

SI_2 = 1800rSI2=1800r  ........(2)

The sum of both interests is Rs 2400.

SI_1 + SI_2 = 2400SI1+SI2=2400

           480r + 1800r = 2400

                       2280r = 2400

r = \dfrac{240}{228}\%r=228240%

r = 1.05%

Thus, the rate is 1.05%.

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