Question

saurbh borrowed 2,40,00 rs from bank form a bank for 4 year at the rate of 8.5 pcpa from his education returned to the bank at end of that period​

Answer 1

Answer:

Step-by-step explanation:

Given: p = 4, α = 15° The equation of the line in normal form is given by We know that, cos 15° = cos (45° – 30°) = cos45°cos30° + sin45°sin30° Cos (A – B) = cos A cos B + sin A sin B So, And sin 15 = sin (45° – 30°) = sin 45° cos 30° – cos 45° sin 30° Sin (A – B) = sin A cos B – cos A sin B Read more on Sarthaks.com - https://www.sarthaks.com/804281/find-the-equation-of-the-line-whose-perpendicular-distance-from-the-origin-is-4-units

Now, by using the formula, x cos α + y sin α = p Now, substitute the values, we get (√3 + 1)x +(√3 - 1) y = 8√2 ∴ The equation of line in normal form is (√3 + 1)x +(√3 - 1) y = 8√2. Read more on Sarthaks.com - https://www.sarthaks.com/804281/find-the-equation-of-the-line-whose-perpendicular-distance-from-the-origin-is-4-units