Question

Savita and Hamida are friends.What is the probability that both will have (1) different birthday? (2) the same birthday.

Answer 1

Answer:

Hamida's bday can also be on any day out of 365 days in the Year.

We assume that these 365 outcomes are equally likely.

(i) If Hamida's bday is different from savita's, the no. Of favorable outcomes for her bday is 365-1= 364

So, P(Hamida' bday is diffrent from Savita's bday)=364/365

(ii) P(Savita and Harmida have the same bday)=

1-P(Both have diffrent bdays)

=1-(364/365) [ using P(not event)=1-P(E)]

=1/365