Question

Savita has rs.27 in the form of 50 paise and 25 paise coins. She has twice as many 25 paise coins as she has 50 paise coins. How many coins of each kind does she have ?

Answer 1

Answer:

Let the actual number of 50 paisa coins, Savita has can be assumed as x

So, the overall worth in rupees =50 \times x = 50x=50×x=50x

Therefore, the amount of 25 paisa coins Savita can have = 2x (as a result of, it is double as several as paisa coins).

So, the total number of value in rupees =25 \times 2x=50x=25×2x=50x

Total Money = 27 Rupees or 2700 paisa

Now, according to the question,

{ (Amount of Money in 50 paisa coins) \times× (Amount of Money in 25 paisa coins) } =2700

\Rightarrow⇒ 50x + 50x = 2700

\Rightarrow⇒ 100x = 2700

\Rightarrow⇒ x=27

So, the number of 50 paisa coins Savita has = 50x

= (27) 50 = 54 coins

Amount of 50 paisa coins Savita has = 13.5 rupees

The number of 25 paisa coins = 50x

The amount of 25 paisa coins = 50 (27) = 54 coins

Amount of 25 paise coins Savita has = 13.5 rupees

Total money Savita = 13.5 rupees + 13.5 rupees = 27 rupees