Savita has rs.27 in the form of 50 paise and 25 paise coins. She has twice as many 25 paise coins as she has 50 paise coins. How many coins of each kind does she have ?
Answers
Answer:
Let the actual number of 50 paisa coins, Savita has can be assumed as x
So, the overall worth in rupees =50 \times x = 50x=50×x=50x
Therefore, the amount of 25 paisa coins Savita can have = 2x (as a result of, it is double as several as paisa coins).
So, the total number of value in rupees =25 \times 2x=50x=25×2x=50x
Total Money = 27 Rupees or 2700 paisa
Now, according to the question,
{ (Amount of Money in 50 paisa coins) \times× (Amount of Money in 25 paisa coins) } =2700
\Rightarrow⇒ 50x + 50x = 2700
\Rightarrow⇒ 100x = 2700
\Rightarrow⇒ x=27
So, the number of 50 paisa coins Savita has = 50x
= (27) 50 = 54 coins
Amount of 50 paisa coins Savita has = 13.5 rupees
The number of 25 paisa coins = 50x
The amount of 25 paisa coins = 50 (27) = 54 coins
Amount of 25 paise coins Savita has = 13.5 rupees
Total money Savita = 13.5 rupees + 13.5 rupees = 27 rupees