Question

Savita's age is four times the difference of her age after 4 years and her 3 years back. Find Savita's present age.

Answer 1

Hi Mate !!


Let Savita's age be x

• Her age after 4 years will be ( x + 4 )

• Her age before 3 years was ( x - 3 )


• Savita's age is four times the difference of her age 4 years and her 3 years back.

x = 4 ( x + 4 - ( x - 3 ) )

x = 4 ( x + 4 - x + 3 )

x = 4 ( 7 )

x = 28

And hence , Savita's age is 28 years !!

Answer 2

Let present age of savita be x,

After 4 years, age = (x+4) years
3 years back, age = (x-3) years

===============

According to the question,

x = 4[ (x + 4)-(x - 3)]

x = 4[x + 4 - x + 3]

x = 4[ 7]

x = 28

Present age of savita =x = 28 years



I hope this will help you

-by ABHAY