Question

Say 40% of the class is female. What is the probability that 6 of the first 10 students walking in will be female?

Answer 1

Total no of boys in class be 50 and girls are 40%

boys=60℅

the math is very simple and we have 2 solutions!

Solution 1

We have 50 students. 50 is the half of 100 because 50x2=100

40% is equal to 40/100

As we all probably know from fractions if we divide one of the numbers in the fraction, we have to divide with the same number the other one.

So, 40/100 is equal to 20/50 because 100/2=50 and 40/2=20

20/50 (which is equal to 40/100 or 40%) says that 20 girls are in the class

And if we do the subtraction, it’s 50–20=30

Answer: There are 30 boys in the class

Solution 2

We have 50 students and 40% are girls.

If we multiply 50 with 2 it gives us 100 (50x2=100)

40% is equal to 40/100

So there are forty girls in the class with supposedly 100 students.

If we do the subtraction it’s 100–40=60

And then we divide it by 2 because we multiplied the number of the students earlier 60/2=30

Answer: There are 30 boys in the class

Hope I made it clear,

Answer 2

Answer:

There are 20 girls and 30 boys in the class

Step by step explanation:

Total no of students in class be 50 and girls are 40%

boys=60℅

We have 50 students.

50 is the half of 100 because 50 x 2 = 100

40% is equal to 40/100

As we all probably know from fractions if we divide one of the numbers in the fraction, we have to divide with the same number the other one.

So, $\frac{40}{100}$ is equal to $\frac{20}{50}$ because $\frac{100}{2}$ = 50 and $\frac{40}{2}$ = 20

$\frac{20}{50}$ (which is equal to 40/100 or 40%) says that 20 girls are in the class

And if we do the subtraction, it’s 50–20=30

∴ There are 30 boys in the class