Question

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Answer 1

Step-by-step explanation:

8) here, (3x +2)(3x-2) ...... 1

as we know that,

(a+b)(a-b) =a^2-b^2

so eq. 1 can be written as

$(3x) ^{2} - {2}^{2} \\ or \: \: 9 {x}^{2} - 4$

which is required answer

10) i)

${99}^{2} =( {100 - 1})^{2} \: now \: solve \: it \: as \:( a - b)^{2} \\ ii) \: \: solve \: it \: as \: a ^{2} - b ^{2} =( a + b)(a - b)$

question 7 and 9 are in pic