say answers of these 2 questions
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siddhartharao77:
I didn't understand 1st question.Can i solve the 2nd one?
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60. Let the angles of the triangle be 4x,x,x.
4x + x + x = 180
6x = 180
x = 30.
The angles of the triangle are 4 * 60, 30 ,30 = 120,30,30.
That means Angle A = 120, B = 30 and C = 30.
We know that a/Sin A = b/Sin B = c/Sin c = K
a = K Sin A = K sin 120 = root 3/2.
b = K sin B = K sin 30 = 1/2.
c = K sin C = k sin30 = 1/2.
The ratio of largest side to the perimeter = root 3/2/(root 3/2 + 1)
= root 3/root 3 + 2.
Hence the value of k = 3.
4x + x + x = 180
6x = 180
x = 30.
The angles of the triangle are 4 * 60, 30 ,30 = 120,30,30.
That means Angle A = 120, B = 30 and C = 30.
We know that a/Sin A = b/Sin B = c/Sin c = K
a = K Sin A = K sin 120 = root 3/2.
b = K sin B = K sin 30 = 1/2.
c = K sin C = k sin30 = 1/2.
The ratio of largest side to the perimeter = root 3/2/(root 3/2 + 1)
= root 3/root 3 + 2.
Hence the value of k = 3.
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