Question

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Answer 1

Answer:

Sum of interior angles of an n sided polygon = (2n−4)×90 degrees.

Let us find the sum of the interior angles of a heptagon.

Heptagon is a polygon with 7 sides.

⇒n=7

Sum of interior angles of a heptagon =(2×7−4)×90∘.

⇒10×90⇒=900

⇒900∘

One angle of a heptagon=7900=128.57∘

So one angle of a triangle=180−128.57=51.43∘

Another angle is 180−102.85=77.14∘

So the sum of  m∠A+m∠B+m∠C+m∠D+m∠E+m∠F+m∠G=77.17×7=540∘

Answer 2

Answer:

360

Step-by-step explanation:

sum of the angles in the triangle ACE and sum of the angles in the triangle DBF