Question

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Answer 1

Answer:

Ans (c)

$\frac{ sinB }{ sinC }$

Step-by-step explanation:

Refer attached image for roughdiagram of your question.

sinB = AD/AB --------( 1 )

sinC = AD/AC --------( 2)

cosB = BD/AB

cosC = CD/AC

tanB = AD/BD

tanC = AD/CD

dividing 1 by 2

$\frac{ sinB}{ sinC } = \frac{ \frac{AD}{AB} }{ \frac{AD}{AC} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \frac{ sinB}{ sinC } = \frac{AD}{AB} \times \frac{AC}{AD} \\ \\ \frac{ sinB}{ sinC } = \frac{AC}{AB} \: \: \: \: \: \: \: \: \: \: \: \:$

Ans (c)