Question

say the answer with steps​

Answer 1

$3 {x}^{2} y + 6xy + 3y$

$3 {x}^{2} y + 3xy + 3xy + 3y = 0$

$3xy(x + 1)3y(x + 1) = 0$

$(3xy + 3y)(x + 1) = 0$

$3xy + 3y = 0...(1)$

$x + 1 = 0$

$\orange{\therefore x = - 1}$

$\tt substituting \: (x = - 1) \: in \: (1)$

$\implies 3( - 1)y + 3y = 0$

$\implies - y + 1 = 0$

$\orange{\therefore y = 1}$

HOPE THIS HELPS!!