Question

say the correct answer please of number 8.​

Answer 1

QUESTION :- Find the smallest number by which 2560 must be multiplied so that the product is a perfect cube.

ANSWER :-

By Prime factorization we get

2560 = 5 × 2 × 2× 2 × 2× 2× 2× 2× 2× 2

Only 5 is left with no triplets.

Since the prime factorization are not in triplets.

∴ So to make it a perfect cube, the above number should be multiplied with $5 \times 5 = 25$.

Hence the smallest number to be multiplied to 2560 is 25 to make is perfect cube.

Answer 2

Answer:

QUESTION :- Find the smallest number by which 2560 must be multiplied so that the product is a perfect cube.

ANSWER :-

By Prime factorization we get

2560 = 5 × 2 × 2× 2 × 2× 2× 2× 2× 2× 2

Only 5 is left with no triplets.

Since the prime factorization are not in triplets.

∴ So to make it a perfect cube, the above number should be multiplied with 5 \times 5 = 255×5=25 .

Hence the smallest number to be multiplied to 2560 is 25 to make is perfect cube.