Math, asked by shubhajeetmahato009, 5 days ago

say the correct answer please step by step​

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Answered by negivardhan993
2

Explanation:

\mathsf{x- \frac{2x+8}{3}=\frac{1}{4}(x- \frac{2-x}{6})-3}

\mathsf{==>4(x- \frac{2x+8}{3})=x-\frac{2-x}{6}-3}

\mathsf{==>4x-\frac{8x+32}{3}=x - \frac{2-x}{6}-3}

\mathsf{==>\frac{12x-8x-32}{3}=\frac{6x-2+x-18}{6}}

\mathsf{==>\frac{4x-32}{3}=\frac{7x-20}{6}}

\mathsf{==>6(4x-32)=3(7x-20)}

\mathsf{==>24x-192=21x-60}

\mathsf{==>24x-21x=-60+192}

\mathsf{==>3x=132}

\mathsf{x=\frac{132}{3}=44}

Answer: x = 44

I hope this helps. :D

Answered by arpanaial06
0

Answer:

hope it will help you dear

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