Question

say the correct answer step by step please
question 2)​

Answer 1

Answer:

Let the original number be x.

According to the question we can write as

$\sf \: \frac{2}{3} x+20x$

On rearranging x−(2/3)x=20

Now taking the L.C.M od 1 and 3 is 3

(3x−2x)/3=20

$\sf \: \frac{x}{3} =20$

Again by transposing x=60

So the original number is 60