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Given equation is 3x^ 4 −27x^ 3 +36x^ 2 −5
Comparing with the standard form ax
3 +bx 2 +xc+d=0, we get
a=3,b=−27,c=36,d=−5
S 1 =α+β+γ=− b /a
and S 2 =αβ+αγ+βγ= c/a
S 1 =−(− 27/3 )=9
S 2 = 36/3 =12
Therefore, S1 +S2 =9+12=21
hope it helps
plz mark brainliest tyvm!!!
( just a question .,how is this gr10 type question in jee mains???)( i thought jee mains was hard af)
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