Question

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Answer 1

Answer:

We have,

Let the radius of circle r=4cm.

Angle θ=30

o

Area of sector of circle

=

360

o

θ

×πr

2

=

360

o

30

o

×π×4×4

=

12

π

×16

=

3

4π

=

3

4

×3.14

=4.186cm

2

Area of major sector = Area of circle-area of minor sector

=πr

2

−4.186

=3.14×4×4−4.186

=3.14×16−4.186

=50.24cm.

2

Hence, this is the answer.

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