Question

say wirh statement say Q no.10,11,12,13,14

Answer 1

Here your answer goes

❣ Answer :- 1  ❣

$\leq Step :-1 \geq$

Let the third side be x

Then the other two sides will be 3 x +2

Perimeter = 67 cm

$\leq Step :- 2 \geq$

$x + ( 3x +2 ) + ( 3x +2 ) = 67$

7x +4 = 67

7x = 67 - 4

7x = 63

x = $\frac{63}{7}$

x = 9

Therefore , the third side of an isosceles triangle is 9cm

$\leq Step :- 3 \geq$

Other two sides = 3x + 2

Put the value of x

3(9) + 2

27 + 2

==> 29 cm

❣ Answer :- 2  ❣

$\leq Step :- 1 \geq$

Let the breadth be x

Then length be 2x - 16

We know that perimeter of a rectangle = $2 ( l +b ) = 100 cm$

$\leq Step :- 2 \geq$

2 ( 2x - 16 + x ) = 100

3x - 16 = 100/2

3x - 16 = 50

3x = 50 + 16

3x = 66

x = 66/3

x = 22 cm

$\leq Step :- 3 \geq$

Length  = 2x - 16

Put the value of x

2(22) - 16

==> 44 - 16

==> 28 cm

Therefore length of a rectangle = 28 cm and Breadth = 22 cm

❣ Answer :- 3  ❣

$\leq Step :- 1 \geq$

let first consecutive integer be x

Second will be x + 1

Sum = 63

$\leq Step :- 2 \geq$

x + x +1 = 63

2x + 1 = 63

2x = 63 - 1

2x = 62

x = 62/2

x = 31

$\leq Step :- 3 \geq$

2nd number = x + 1

Put the value of x

31 +1 = 32

Therefore , the first consecutive  integer is 31 and second is 32

❣ Answer :- 4  ❣

$\leq Step :- 1  \geq$

Let the number of notes of Rs. 10 be x

The number of notes of  Rs. 50 - x

Sum = 800

$\leq Step :- 2 \geq$

According to the question ,

10x + 20 ( 50 - x ) = 800

10x + 1000 - 20x = 800

-10x = 800 - 1000

-10x  = -200

x = $\frac{-200}{-10}$

x = 20

Therefore , the number of denomination of Rs . 10 = 20

$\leq Step :- 3 \geq$

Then the number of denomination of Rs . 20  is 30 as below :-

50 - x

Put the value of x

==> 50 -20

==> 30

❣ Answer :- 5  ❣

$\leq Step :- 1 \geq$

Let the boys be x

Let the girls be 2/5 * x

Total number of student = x + 2/5 x

$\leq Step :- 2 \geq$

According to the  question ,

x + 2/5 x = 49

7/5 x = 49

x = 49 * 5/7

x = 35

Therefore the number of boys are 35