Chemistry, asked by alanvraj, 8 hours ago

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Answered by Rider16789
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Answer:

Electronic Configuration

1. C - Carbon: 1s^2 2s^2 2p^6 3s^2

2. A - Sulphur: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^2

Bohr Atom Model

1. C: B.A.M. of Carbon will be 3 concentric circles, with each circle having dots(electrons) in the following number:

  • innermost circle (k shell): 2 electrons
  • innermost circle (k shell): 2 electronssecond circle (l shell): 8 electrons
  • innermost circle (k shell): 2 electronssecond circle (l shell): 8 electronsoutermost circle (m shell): 2 electrons

2. S: B.A.M. of Sulphur will be 4 concentric circles with each circle having dots(electrons) in the following number:

  • innermost (k): 2 electrons
  • innermost (k): 2 electronsSecond (l): 8 electrons
  • innermost (k): 2 electronsSecond (l): 8 electronsThird (m): 18 electrons
  • innermost (k): 2 electronsSecond (l): 8 electronsThird (m): 18 electronsFourth (n): 4 electrons

Hope this helps.

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