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Answers
Answer:
As we know by the second law of motion that Force =Mass x Acceleration
so we will use it to solve this question.
a) Acceleration, a = (final velocity - initial velocity)/time taken
Initial velocity, u = 0 m/s (as it starts from rest)
final velocity , v= 120 m/s
time taken = 3s (as given that we have to find the answer between time interval 0 to 3s )
Acceleration = (v-u)/t
= 120-0/3
= 40 m/s^2
Mass, m = 100g = 0.1 kg
Force , F= m x a
F= 0.1 x 40
F= 4 Newton
b) Force =Mass x Acceleration
Acceleration, a = (final velocity - initial velocity)/time taken
Initial velocity, u = 120 m/s
final velocity , v= 0 m/s (as it comes to rest)
time taken = 4s (as given that we have to find the answer between time interval 6 to 10s and 10-6=4)
Acceleration = (v-u)/t
= 0-120/4
= -30 m/s^2
Mass, m = 100g = 0.1 kg
Force , F= m x a
F= 0.1 x -30
F= -3 Newton ( - sign indicates that the force is frictional and is applied by the surface on the object to stop it)
c) Yes, between time interval of 3s to 6s no force acted on object .
It is because;-
Force =Mass x Acceleration
Acceleration, a = (final velocity - initial velocity)/time taken
Initial velocity, u = 120 m/s
final velocity , v= 120 m/s
time taken = 3s (as given that we have to find the answer between time interval 3s to 6s , 6-3=3)
Acceleration = (v-u)/t
= 120-120/3
= 0 m/s^2
Mass, m = 100g = 0.1 kg
Force , F= m x a
F= 0.1 x 0
F= 0 Newton
Hence Justified