Question

Schin got 60% marks in Maths and 3 marks less than Maths in Science. If the total marks are 150 . how many marks he scored in science?​

Answer 1

Given :

Sachin got 60% marks in Maths and 3 marks less than Maths in Science. If the total marks are 150

• 1) 90 2) 95 3) 87 4) 63

To find :

• Marks scored in science

Solution :

★ Total marks = 150

Consider marks in maths be x

★ Marks in maths = 60%

★ Marks in Science = 3 marks less than maths

• According to the given condition

★ Marks in maths

• As we know that

★ Percentage = Obtained value/total value × 100

→ 60 = x/150 × 100

→ 60 = 10x/15

→ 60 × 15 = 10x

→ x = 60 × 15/10

→ x = 90

•°• Marks scored in maths = 90

★ Marks in Science = 3 marks less than maths

→ Marks in maths - 3

→ 90 - 3

→ 87

•°• Marks scored in science is 87

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Answer 2

${\bf{Given\::}}$

• Schin got 60% marks in Maths.

• His Science mark is '3 marks less' than Maths mark.

• The total marks are 150 (in each subject).

$\\ {\bf{To\: Find\::}}$

• The marks he scored in science.

$\\ {\bf{Solution\::}}$

Let,

• Sachin got x marks in Math.

It is given that,

➣ Schin got 60% marks in Maths.

That means,

$\dashrightarrow\:\tt{\dfrac{x}{150}\times{100}\:=\:60}$

$\dashrightarrow\:\tt{\dfrac{x}{15}\times{10}\:=\:60\:}$

$\dashrightarrow\:\tt{\dfrac{x}{15}\:=\:\dfrac{60}{10}\:}$

$\dashrightarrow\:\tt{x\:=\:6\times{15}\:}$

$\dashrightarrow\:\bf{x\:=\:90\:}$

Hence,

✯ Sachin got 90 marks in Math.

And,

➣ His Science mark is '3 marks less' than Maths mark.

That means,

➛ 90 - 3

➛ 87

Hence,

✯ Sachin scored 87 marks in science.

Now,

➣ Percentage in science is,

➠ $\tt{\dfrac{87}{150}\times{100}\:}$

➠ $\tt{\dfrac{87}{15}\times{10}\:}$

➠ $\tt{\dfrac{87}{3}\times{2}\:}$

➠ $\tt{29\times{2}\:}$

➠ $\bf\pink{58\%\:}$

∴ Sachin scored 58% in science.