Question

Scholarship details of side 40 cm are to be fixed in a hall of dimension 2.4 them by 69 find the number of tiles required

Answer 1

Answer

24 cm

Step-by-Step Explanation

Area of the hall=24*1600cm^2

=38400cm^2.

Area of each tile=40^2

=1600cm^2.

So, number of tiles required =Area of the hall/area of each tile

=38400/1600

=24.

Hope this helps you buddy!!

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Answer 2

Answer:

103.5

Step-by-step explanation:

Given,

Area of hall = 24 × 6900 cm²

= 165600 cm²

Area of tile = 40 × 40

= 1600 cm²

so,

Number of tiles required = Area of the hall ÷ Area of each tile

= 165600 ÷ 1600

= 103.5

Hope this helps you !!!