Question

science physics class 11

Answer 1

C
.....................
.

Answer 2

Answer:

C) g cot θ

Explanation:

The free body diagram of the block is as shown in the figure. N is the normal reaction exerted by wedge on the block.

The wedge moves towards left with acceleration ‘a’, then the component of acceleration of block normal to the plane is ‘a’ sinθ.

Applying Newtons second law to the block normal to plane.

mg cos – N = ma sinθ

For N to be zero

a = g cotθ.

Hence the friction shall be zero when a = g cotθ.