Scon thee magn This forces are such that the of magnitude & en and their gecoitant se perpendicular to the Smaller force and magnitude resultant ic 12. Then the tacel all of the magnitude
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Let the smaller force be B ,the larger force be A, resultant being C.
Given: ∣A∣+∣B∣=18,∣C∣=12
A,B,C simply form a right angled triangle with base B vector,hypotenuse being A.
So, you have one equation with you: A+B=18
A2=B2+C2A2−C2=B2(A+B)(A−B)=144(A−B)18=144A−B=18144=8
So simply solving both equations: A-B=8 and A+B=18
Adding both:
2A=26
A=13
B=5
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