Question

scooter acquires a velocity of 36 kilometre -1 in 2 seconds after the start the acceleration of the scooter is​

Answer 1

v=36km/hr=36×1000/60=10m/s

a=v-u/t

=10-0/2=5m/s^2

Answer 2

v=36km/hr=36×1000/60=10m/s

a=v-u/t

=10-0/2=5m/s^2

After the start acceleration of the scooter is 5m/s^2.

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