scooter acquires a velocity of 36 kilometre per hour in 5 seconds after the start calculate the acceleration of the scooter..plz help me
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Answer:
acceleration of scooter is 18m/s*2
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Answer:
Explanation:
From the equation of motion, we get,
v = u + a t
Initial velocity, u=0 [ Since, body starts from rest ]
Final velocity, v=36 km/h = 36 x Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. [1 km/h=Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.]
Therefore, v = 10 m/s
t = 10 sec
v = u + a t
v - u = a t
Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.=a
Therefore, a = 1 m/s2
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