Question

Scooter charges at a certain place consists of fixed charges and the remainine depending upon the
distance travelled in kilometers. If a person travels 10 km, he pays R 28 and for wavelling
* Formulate simultaneous equations and hence find the fixed charges and the rate per km​

Answer 1

Step-by-step explanation:

Given Scooter charges at a certain place consists of fixed charges and the remaining depending upon the  distance travelled in kilometers. If a person travels 10 km, he pays R 28 and for travelling  16 km he pays Rs 43. Formulate simultaneous equations and hence find the fixed charges and the rate per km​

• Let x be the fixed charge and y be the charge dependent on distance per km
• Now travelling 10 km total charge as Rs 28
• So equation will be x + 10 y = 28-----------1
• After travelling 16 km total charge was Rs 43
• So equation will be x + 16y = 43------------2
• Now subtracting the equations we get
• So   x + 10 y = 28
•  So  x + 16 y = 43
•                  -6y = - 15
•                So y = 5/2
• Substituting y = 5/2 in the above equation we get
•  So x + 10 y = 28
•   So x + 10 (5/2) = 28
• So x + 25 = 28
• Or x = 28 – 25
• Or x = 3

So fixed charge is Rs 3 and charge dependent on distance is Rs 2.50

Reference link will be

https://brainly.in/question/4579814

Answer 2

Answer:

Step-by-step explanation:

Given Scooter charges at a certain place consists of fixed charges and the remaining depending upon the  distance travelled in kilometers. If a person travels 10 km, he pays R 28 and for travelling  16 km he pays Rs 43. Formulate simultaneous equations and hence find the fixed charges and the rate per km​

Let x be the fixed charge and y be the charge dependent on distance per km

Now travelling 10 km total charge as Rs 28

So equation will be x + 10 y = 28-----------1

After travelling 16 km total charge was Rs 43

So equation will be x + 16y = 43------------2

Now subtracting the equations we get

So   x + 10 y = 28

So  x + 16 y = 43

                -6y = - 15

              So y = 5/2

Substituting y = 5/2 in the above equation we get

So x + 10 y = 28

 So x + 10 (5/2) = 28

So x + 25 = 28

Or x = 28 – 25

Or x = 3

So fixed charge is Rs 3 and charge dependent on distance is Rs 2.50