scooter is bought for 32,000 its value depreciates at 10% per annum what will be its value after 2 years
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CP = 32000
Depriciation Rate = 10%
so, let value after 2 years be x
x = CP (1-R%)
x = 32000 (1-10%)
x = 32000 (1 - 10/100)
x = 32000 (1- 1/10)
x = 32000 (9/10)
x = 3200 x 9
x = 28,800
So Value after depriciation = x = 28,800
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