Question

scooter starts from rest and moves in a straight line with constant acceleration and covers a distance of 64 m in 4 seconds calculate the acceleration and its final velocity at what time does scooter has covered half of the total distance
Find with step by step explanation
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Answer 1

Answer:

Explanation:

Given,

Initial velocity of the scooter, u = 0 m/s

Distance covered by the scooter, s = 64 m

Time taken by the scooter, t = 4 seconds.

To Find,

Acceleration, a

Final velocity, v and,

At what time taken by scooter to cover half of the total distance.

Formula to be used,

1st equation of motion, i.e, v = u + at

2nd equation of motion, i.e, s = ut + 1/2 at²

Solution,

Putting all the values, we get

s = ut + 1/2 at²

⇒ 64 = 0 × 4 + 1/2 × a × (4)²

⇒ 64 = 1/2 × a × 16

⇒ 64 = 8a

⇒ 64/8 = a

⇒ a = 8 m/s².

Hence, the acceleration of the scooter is 8 m/s².

No, the Final velocity of the scooter,

v = u + at

⇒ v = 0 + 8 × 4

⇒ v = 8 × 4

⇒ v = 32 m/s.

Hence, the final velocity of the scooter is 32 m/s.

Now, time taken by scooter to covered half of the total distance,

s = ut + 1/2 at²

⇒ 64/2 = 0 × 4 + 1/2 × 8 × t²

⇒ 64 = 8t²

⇒ 64/8 = t²

⇒ 8 = t²

⇒ t² = 2√2 seconds.

Hence, the scooter covers half of the total distance in 2√2 seconds.

Answer 2

Answer. V=32 m/s.

Hope it helps_