Question

scooter starts from rest and travels with uniform acceleration of 2 metre per second square for 6 second what is the velocity acquired ? calculate the distance travelled in 6 seconds​

Answer 1

Answer:

The velocity acquired is 12 m/s and the distance covered is 36 m

Explanation:

Case 1 :

(v-u)/t = a

v/t = a (since u = 0)

v = a×t

=(2×6) m/s

v = 12 m/s

Case 2 :

d = ut + 1/2×a×t^2

=(0×6) + 1/2×2×(6)^2

= 0 + 36

= 36 m