se by using the
of
Find the solution set by using
mechod
method
of elimination
Substitution
x + 8y = 15
34. y .o
+ 8y = 15
by
a
رن) -
3- y =
3a = 9
= 0
(ii)
x = y
3
Answers
Step-by-step explanation:
(i) By elimination method:
x + y = 5————-(1)
2x – 3y = 4 ————(2)
Multiplying equation (1) by 2,
2x + 2y = 10 —————-(3)
Subtracting equation (2) from equation (3),
5y = 6
y = 6/5 ————-(4)
Substituting the value in equation (1),
x = 5 – 6/5 = 19/5
x = 19/5 , y = 6/5
By substitution method:
From equation (1),
x = 5 – y ————-(5)
Put the value of x in (2)
2(5-y) – 3y = 4
-5y = – 6
y = 6/5
Substituting the value in equation (5)
x = 5 – 6/5 = 19/5
x = 19/5 ; y = 6/5
(ii) By elimination method:
3x + 4y = 10 ———-(1)
2x – 2y = 2———(2)
Multiplying equation (2) by 2,
4x – 4y = 4 ————(3)
Adding equation (1) and (3),
7x = 14
x = 2 —————(4)
Substituting in equation (1),
6 + 4y = 10
4y = 4
y = 1
Thus, x = 2, y = 1
By substitution method:
From equation (2),
x = 1 + y ———- (5)
Put the value of x in equation (1),
3(1+y)+4y = 10
7y = 7
y = 1
Substituting the value in equation (5),
x = 1+1=2
x = 2, y = 1
(iii)By elimination method:
3x – 5y – 4 = 0 ————(1)
9x = 2y + 7
9x – 2y – 7 = 0 ————–(2)
Multiplying equation (1) by 3,
9x – 15y – 12 = 0 ————(3)
Subtracting equation (3) from equation (2),
13y = -5
y = -5/13
Substituting in equation (1),
3x + 25/13 – 4 = 0
3x = 27/13
x = 9/13
x = 9/13 ; y = -5/13
By substitution method:
From equation (1),
x = 5y+4/3 ————–(5)
Putting this value in equation (2),
9(5y+4/3) – 2y – 7 = 0
13y = -5
y = ‑5/13
Substituting the value in equation (5),
x = [5(-5/13)+4]/3 = 9/13
Thus, x = 9/13 and y = ‑5/13
(iv) By elimination method
x/2 + 2y/3 = -1
3x + 4y = -6 ———–(1)
x – y/3 = 3
3x – y = 9 —————-(2)
Subtracting equation (2) from equation (1),
5y = -15
y = -3 —————(3)
Substituting this value in equation (1),
3x – 12 = -6
3x = 6
x = 2
Hence, x = 2, y = −3
By substitution method:
From equation (2),
x = y+9/3———– (5)
Putting this value in equation (1),
3(y+9/3) + 4y = -6
5y = -15
y = -3
Substituting the value in equation (5),
x = -3+9/3 = 2
∴ x = 2, y = −3