Question

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ise
ise
13. A force of magnitude 10N acts on a particle
at an angle 60° with the horizontal. Horizon-
tal components of this force is
1) 10N
2) 5N 3) 53N 4) 10/3N
​

Answer 1

Answer:

Correct option is

A

10

3

N

The resultant force acts due north.

⇒ The horizontal components of the two forces cancel

⇒ 10=Psin30=

2

P

=10⇒P=20N

∴ Resultant R=Pcos30=20×

2

3

=10

3

N.

solution