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प्रा समीकरण संतुलित कीजिए
Fe+Ho - fez Ou + H2 2
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Answer:
Consider the following,
work done is written as W = F.s = FsCosθ here F is the force applied, s is the displacement caused such that
F = mg = 10 X 10 = 100 N s
W( horizontal direction)= FsCos(0)=500J , θ is the angle between (vectors) F and s now,
as F and s are perpendicular for vertical direction, θ = 90 thus, W = FsCos90 = 0
Explanation:
Given
a
2
=13 and a
5
=25
We know that
a
n
=a+(n−1)d
∴a
2
=a+(2−1)d
⇒13=a+(2−1)d
⇒a+d=13 ...(i)
and a
5
=a+(5−1)d
⇒25=a+4d
⇒a+4d=25 ...(ii)
Now, subtracting (i) from (ii), we get
3d=12
⇒d=4
Now a+d=13 [from (i)]
⇒a=9
Hence, a
7
=a+6d=9+6(4)
⇒a
7
=33
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