Question

Sea water contains 53 PPM of Na2CO3 find mass of Na2CO3 present in a glass of water which is 250ml of capacity and take density of water as 1g/ml

Answer 1

The mass of present in water is
Explanation:

Concentration in ppm =

Given ; Concentration in ppm = 53

mass of solute = x g

Mass of solution = mass of solute  + mass of water = x g + 100 g


Thus the mass of  present in water is 


Thus the mass of present in water is

ppm=mass of solute/volume of solution multiplied by 10^6
here 53 ppm indicate 53g of na2co3 in 1000ml

Answer 2

Explanation:

The given question is incomplete. the complete question is :

Sea water contains 53 ppm of Na2Co3 . Find mass of Na2Co3 present in 100 g of water.

The mass of Na_2CO_3Na

2

CO

3

present in water is 5.3\times 10^{-3}g5.3×10

−3

g

Explanation:

Concentration in ppm =\frac{\text {mass of solute}}{\text {mass of solution}}\times 10^6

mass of solution

mass of solute

×10

6

Given ; Concentration in ppm = 53

mass of solute Na_2CO_3Na

2

CO

3

= x g

Mass of solution = mass of solute Na_2CO_3Na

2

CO

3

+ mass of water = x g + 100 g

53=\frac{x}{(x+100)}\times 10^653=

(x+100)

x

×10

6

x=5.3\times 10^{-3}gx=5.3×10

−3

g

Thus the mass of Na_2CO_3Na

2

CO

3

present in water is 5.3\times 10^{-3}g5.3×10

−3

g