sea water contains 53 ppm of Na2CO3.Find mass of Na2CO3 present in a glass of water.
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Answer:
Concentration in ppm =
mass of solute/mass of solution×10-6
mass of solute Na2Co3=X g
mass of solution =mass of soluteNa2co3× mass of water=Xg+100
53=X g/X g+100 ×10-6
CONCENTRATION in ppm=5.3×10-3
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