Question

Sea water contains an average of 1.08 x 103 ppm of Na+ and 270 ppm of SO4 -2 . Calculate a. The molar concentration of Na+ and SO4 -2 given that the average density of sea water is 1.02 g/mL b. The pNa and pSO4 for sea water

Answer 1

Answer:

Molarity is defined as the number of moles of solute divided by volume of solution in liters.

Molarity is also called Molar concentration.

Answer 2

The average density of sea water is $=4.79*10^{-2}mol/L$.

Explanation:

The an average of

$=1.08*10^{3}$$ppm.$

The density of sea water $=1.02 g/mL.$

The molar concentration of $N_{a} ^{+}N_{a} ^{+}=1.08*10^{3} ppm$

$=1080 mg/L$

$=1080*10^{-3}/23g/mol$

$=0.046M$ $SO4_{2}$$=\frac{270*10^{-3}}{96}$

$=2.81*10^{-3}$

$=4.79*10^{-2}mol/L$