Sea water contains roughly 28.0 g of nacl per liter
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Explanation:
58.5 g/molMolecular weight of NaCl28 gWeight of NaCl1 literVolume of the solution
M=\frac{wt*1000}{mw*volume}M=mw∗volumewt∗1000
M=\frac{28*1000}{58.5*1000}M=58.5∗100028∗1000
M=0.479\,mol/LM=0.479mol/L
Molarity formula
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