Question

search by substitution method : 2y - x =0 eq1 , 3x+4y =20 eq 2​

Answer 1

The Given Equation are:-

$\\\sf{ 2y - x =0 \: \: \: \: \: \: - - - - (1)}$

$\sf{ 3x + 4y =20 \: \: \: \: \: \: - - - - (2)}$

From Equation 1, We get

$\\\sf - x = - 2y$

$\sf ~~x =2y$

$\text{\bf On Substituting x=2y in Equation(2),we get}$

$\\ →\sf3(2y) + 4y = 20$

$→\sf6y + 4y = 20$

$→\sf10y = 20$

$→\sf \cancel{10}^{1} y = \cancel{ 20}^{2}$

$→\sf \: y = 2$

Putting y= 2 in Equation (1), we get

$\\→\sf2 \times 2 - x = 0$

$→\sf - x = - 4$

$→\sf x = 4$

• Hence the Solution of the given equation is x=4 , y=2