Question

search the 12th question ​

Answer 1

I have taken A instead of theta

tan²A-sin²A=tan²A x sin²A

L.H.S.=tan²A -sin²A

sin²A/cos²A-sin²A       [tan²A=sin²A/cos²A]

sin²A-cos²A x sin²A/cos²A

sin²A(1-cos²A)/cos²A

sin²A x sin²A/cos²A

sin²A x tan²A           [sin²A/cos²A = tan²A}

therefore R.H.S.

hence proved