Math, asked by shivM6393, 9 months ago

Searches related to The two sides of a rectangle are x and x + 1. If the length of the diagonal of the rectangle is 5, then what is the area of the rectangle?

Answers

Answered by pandaXop
5

Area of Rectangle = 12

Step-by-step explanation:

Given:

  • Two sides of rectangle are x and x + 1 .
  • Length of diagonal of rectangle is 5 m.

To Find:

  • What is the area of rectangle ?

Solution: Let ABCD be a rectangle in which :-

  • Length = AB = x
  • Breadth = BC = (x + 1 ) m
  • Diagonal = AC = 5 m

We know that the measure of each angle of rectangle is of 90°. So applying Pythagoras Theorem in ABC

  • In ∆ABC → AB (Base) , BC (Perpendicular) and AC (Diagonal)

Pythagoras Theorem Hypotenuse² = Base² + Perpendicular²

\implies{\rm } AC² = AB² + BC²

\implies{\rm } 5² = x² + (x + 1)² { By using (a + b)² = a² + 2ab + b² }

\implies{\rm } 25 = x² + (x² + 2x + 1²)

\implies{\rm } 25 = 2x² + 2x + 1

\implies{\rm } 0 = 2x² + 2x + 1 – 25

\implies{\rm } 0 = 2x² + 2x – 24

\implies{\rm } 0 = 2 (x² + x – 12 )

\implies{\rm } 0 = x² + x – 12

\implies{\rm } 0 = x² + 4x – 3x – 12

\implies{\rm } 0 = x ( x + 4 ) – 3 ( x + 4 )

\implies{\rm } 0 = ( x + 4 ) ( x – 3 )

\implies{\rm } x + 4 = 0 , x – 3 = 0

\implies{\rm } x = – 4 , x = 3

Since, x cannot be negative so we will take the value of x = 3

So, The sides are:- Length = x = 3 m and

Breadth = x + 1 = 3 + 1 = 4 m

Area of rectangle = Length \times Breadth sq units

\implies{\rm } Area = (3 \times 4)

\implies{\rm } Area = 12

Hence, The area of rectangle is 12 m².

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