Question

sec 0+1-tan 0 tan O+ sec 0-1
32. Prove:
sec 0+1+tan 0 tan 0-sec 0+1
2 sec​

Answer 1

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According to given sum,

sin (1+tan)+cos (1+cot)=sec+cosec

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin^2/cos+cos)/tan

=> (1+tan)(sin^2+cos^2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

HENCE PROVED.

PLEASE MARK IT AS BRAINLIEST AND GIVE IT A THANKS AND 5 STAR PLEASE BROTHER PLEASE.....