Question

sec 0 cos ec(90° - 0) – tan 0 cot(90° – 0)+ (sin? 35° + sinº 55°)
tan 10°tan 20° tan 45º tan 70° tan 80°​

Answer 1

Step-by-step explanation:

secθcsc(90−θ)−tanθcot(90−θ)+sin255+sin235

=tan10tan101tan20tan201tan60(secθ×secθ)−(tanθ×tanθ)+sin255+cos255

=tan60(sec2θ−tan2θ)+sin255+cos255

=31+1

=32