sec 0 + tan 0 = x then show, sec- tan 0 = 1/x
Answers
Answered by
1
Answer:sec0+tan0=x———-(1)
sec^2theta-tan^2theta=1
(sec theta+tant theta) (sec theta +tan theta)=1
x *(sec theta-tan theta)=1 from (1)
sec theta-tan theta=1/x
Step-by-step explanation:
Similar questions